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6057413305373 is a prime number
BaseRepresentation
bin101100000100101100111…
…1101111110010000011101
3210110002020112210122200202
41120021121331332100131
51243221040301232443
620514423125233245
71163430230362133
oct130113175762035
923402215718622
106057413305373
111a25a30992561
12819b73562825
1334c299c25241
1416d274d05753
15a78795877b8
hex58259f7e41d

6057413305373 has 2 divisors, whose sum is σ = 6057413305374. Its totient is φ = 6057413305372.

The previous prime is 6057413305277. The next prime is 6057413305397. The reversal of 6057413305373 is 3735033147506.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4802247108409 + 1255166196964 = 2191403^2 + 1120342^2 .

It is a cyclic number.

It is not a de Polignac number, because 6057413305373 - 222 = 6057409111069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6057413305673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3028706652686 + 3028706652687.

It is an arithmetic number, because the mean of its divisors is an integer number (3028706652687).

Almost surely, 26057413305373 is an apocalyptic number.

It is an amenable number.

6057413305373 is a deficient number, since it is larger than the sum of its proper divisors (1).

6057413305373 is an equidigital number, since it uses as much as digits as its factorization.

6057413305373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2381400, while the sum is 47.

The spelling of 6057413305373 in words is "six trillion, fifty-seven billion, four hundred thirteen million, three hundred five thousand, three hundred seventy-three".