Base | Representation |
---|---|
bin | 11011110011100000001011… |
… | …11001100011110111011010 |
3 | 22000111020102110100201102122 |
4 | 31321300011321203313122 |
5 | 31003232340332313200 |
6 | 334012453422301242 |
7 | 15610311550465142 |
oct | 1571600571436732 |
9 | 260436373321378 |
10 | 61143253401050 |
11 | 185337875a8537 |
12 | 6a35b7ba27822 |
13 | 2816a26753ca2 |
14 | 11154c64d7922 |
15 | 710722986385 |
hex | 379c05e63dda |
61143253401050 has 24 divisors (see below), whose sum is σ = 113726944125792. Its totient is φ = 24457195382000.
The previous prime is 61143253401017. The next prime is 61143253401079. The reversal of 61143253401050 is 5010435234116.
It is a super-2 number, since 2×611432534010502 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 61143253401050.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9561995 + ... + 14619105.
It is an arithmetic number, because the mean of its divisors is an integer number (4738622671908).
Almost surely, 261143253401050 is an apocalyptic number.
61143253401050 is a deficient number, since it is larger than the sum of its proper divisors (52583690724742).
61143253401050 is a wasteful number, since it uses less digits than its factorization.
61143253401050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5298934 (or 5298929 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 61143253401050 its reverse (5010435234116), we get a palindrome (66153688635166).
The spelling of 61143253401050 in words is "sixty-one trillion, one hundred forty-three billion, two hundred fifty-three million, four hundred one thousand, fifty".
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