Base | Representation |
---|---|
bin | 111001000010111111… |
… | …010011111101000111 |
3 | 12212002212010220121102 |
4 | 321002333103331013 |
5 | 2000421334411312 |
6 | 44050041410315 |
7 | 4265626415516 |
oct | 710277237507 |
9 | 185085126542 |
10 | 61253435207 |
11 | 23a82a70528 |
12 | ba5579999b |
13 | 5a12340523 |
14 | 2d7113267d |
15 | 18d77e5ec2 |
hex | e42fd3f47 |
61253435207 has 2 divisors, whose sum is σ = 61253435208. Its totient is φ = 61253435206.
The previous prime is 61253435183. The next prime is 61253435219. The reversal of 61253435207 is 70253435216.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61253435207 - 28 = 61253434951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61253435227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30626717603 + 30626717604.
It is an arithmetic number, because the mean of its divisors is an integer number (30626717604).
Almost surely, 261253435207 is an apocalyptic number.
61253435207 is a deficient number, since it is larger than the sum of its proper divisors (1).
61253435207 is an equidigital number, since it uses as much as digits as its factorization.
61253435207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 38.
Subtracting 61253435207 from its reverse (70253435216), we obtain a palindrome (9000000009).
The spelling of 61253435207 in words is "sixty-one billion, two hundred fifty-three million, four hundred thirty-five thousand, two hundred seven".
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