Base | Representation |
---|---|
bin | 111001000101110101… |
… | …111010000000000101 |
3 | 12212020012012202110221 |
4 | 321011311322000011 |
5 | 2001021113120003 |
6 | 44054511344341 |
7 | 4300050314623 |
oct | 710565720005 |
9 | 185205182427 |
10 | 61301301253 |
11 | 23aa7a93a45 |
12 | ba698220b1 |
13 | 5a1c22c52a |
14 | 2d77632513 |
15 | 18dbaed7bd |
hex | e45d7a005 |
61301301253 has 2 divisors, whose sum is σ = 61301301254. Its totient is φ = 61301301252.
The previous prime is 61301301163. The next prime is 61301301353. The reversal of 61301301253 is 35210310316.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32990546689 + 28310754564 = 181633^2 + 168258^2 .
It is a cyclic number.
It is not a de Polignac number, because 61301301253 - 213 = 61301293061 is a prime.
It is a super-2 number, since 2×613013012532 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61301301353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30650650626 + 30650650627.
It is an arithmetic number, because the mean of its divisors is an integer number (30650650627).
Almost surely, 261301301253 is an apocalyptic number.
It is an amenable number.
61301301253 is a deficient number, since it is larger than the sum of its proper divisors (1).
61301301253 is an equidigital number, since it uses as much as digits as its factorization.
61301301253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 61301301253 its reverse (35210310316), we get a palindrome (96511611569).
The spelling of 61301301253 in words is "sixty-one billion, three hundred one million, three hundred one thousand, two hundred fifty-three".
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