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61380410173 is a prime number
BaseRepresentation
bin111001001010100011…
…101011101100111101
312212102201001220111221
4321022203223230331
52001201341111143
644110415113341
74302030610105
oct711243535475
9185381056457
1061380410173
1124038706715
12ba90212851
135a3273a144
142d83d46205
1518e3a282ed
hexe4a8ebb3d

61380410173 has 2 divisors, whose sum is σ = 61380410174. Its totient is φ = 61380410172.

The previous prime is 61380410087. The next prime is 61380410183. The reversal of 61380410173 is 37101408316.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59585786404 + 1794623769 = 244102^2 + 42363^2 .

It is a cyclic number.

It is not a de Polignac number, because 61380410173 - 213 = 61380401981 is a prime.

It is a super-3 number, since 3×613804101733 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61380410183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30690205086 + 30690205087.

It is an arithmetic number, because the mean of its divisors is an integer number (30690205087).

Almost surely, 261380410173 is an apocalyptic number.

It is an amenable number.

61380410173 is a deficient number, since it is larger than the sum of its proper divisors (1).

61380410173 is an equidigital number, since it uses as much as digits as its factorization.

61380410173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 34.

Adding to 61380410173 its reverse (37101408316), we get a palindrome (98481818489).

The spelling of 61380410173 in words is "sixty-one billion, three hundred eighty million, four hundred ten thousand, one hundred seventy-three".