Base | Representation |
---|---|
bin | 101100101011101010001… |
… | …1011000100111110000111 |
3 | 210202002011212122111000221 |
4 | 1121113110123010332013 |
5 | 1301103403431242043 |
6 | 21021100344245211 |
7 | 1202451330603511 |
oct | 131272433047607 |
9 | 23662155574027 |
10 | 6141072134023 |
11 | 1a58461138772 |
12 | 832220770807 |
13 | 357140096c08 |
14 | 17332d984bb1 |
15 | a9b23d888ed |
hex | 595d46c4f87 |
6141072134023 has 2 divisors, whose sum is σ = 6141072134024. Its totient is φ = 6141072134022.
The previous prime is 6141072133921. The next prime is 6141072134027. The reversal of 6141072134023 is 3204312701416.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6141072134023 - 237 = 6003633180551 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6141072134023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6141072134027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3070536067011 + 3070536067012.
It is an arithmetic number, because the mean of its divisors is an integer number (3070536067012).
Almost surely, 26141072134023 is an apocalyptic number.
6141072134023 is a deficient number, since it is larger than the sum of its proper divisors (1).
6141072134023 is an equidigital number, since it uses as much as digits as its factorization.
6141072134023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 6141072134023 its reverse (3204312701416), we get a palindrome (9345384835439).
The spelling of 6141072134023 in words is "six trillion, one hundred forty-one billion, seventy-two million, one hundred thirty-four thousand, twenty-three".
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