Base | Representation |
---|---|
bin | 1011011100001100… |
… | …10101010101111101 |
3 | 120212001111002111121 |
4 | 11232012111111331 |
5 | 100034340340331 |
6 | 2453250550541 |
7 | 305131112206 |
oct | 55606252575 |
9 | 16761432447 |
10 | 6142121341 |
11 | 2672081744 |
12 | 1234b98451 |
13 | 76b669835 |
14 | 423a465ad |
15 | 25e35cc11 |
hex | 16e19557d |
6142121341 has 2 divisors, whose sum is σ = 6142121342. Its totient is φ = 6142121340.
The previous prime is 6142121303. The next prime is 6142121417. The reversal of 6142121341 is 1431212416.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3485131225 + 2656990116 = 59035^2 + 51546^2 .
It is a cyclic number.
It is not a de Polignac number, because 6142121341 - 213 = 6142113149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6142124341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3071060670 + 3071060671.
It is an arithmetic number, because the mean of its divisors is an integer number (3071060671).
Almost surely, 26142121341 is an apocalyptic number.
It is an amenable number.
6142121341 is a deficient number, since it is larger than the sum of its proper divisors (1).
6142121341 is an equidigital number, since it uses as much as digits as its factorization.
6142121341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 25.
The square root of 6142121341 is about 78371.6871133957. The cubic root of 6142121341 is about 1831.3560913022.
Adding to 6142121341 its reverse (1431212416), we get a palindrome (7573333757).
The spelling of 6142121341 in words is "six billion, one hundred forty-two million, one hundred twenty-one thousand, three hundred forty-one".
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