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61613431106681 is a prime number
BaseRepresentation
bin11100000001001011111101…
…01011001010110001111001
322002011012000221122220121002
432000211332223022301321
531033433301330403211
6335012453002254345
715656265155160056
oct1600457653126171
9262135027586532
1061613431106681
11186a5122667863
126ab11194b73b5
13284c17728941c
14113016ab3002d
1571ca9039403b
hex38097eacac79

61613431106681 has 2 divisors, whose sum is σ = 61613431106682. Its totient is φ = 61613431106680.

The previous prime is 61613431106641. The next prime is 61613431106683. The reversal of 61613431106681 is 18660113431616.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43510065518656 + 18103365588025 = 6596216^2 + 4254805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61613431106681 is a prime.

It is a super-2 number, since 2×616134311066812 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 61613431106683, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (61613431106683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30806715553340 + 30806715553341.

It is an arithmetic number, because the mean of its divisors is an integer number (30806715553341).

Almost surely, 261613431106681 is an apocalyptic number.

It is an amenable number.

61613431106681 is a deficient number, since it is larger than the sum of its proper divisors (1).

61613431106681 is an equidigital number, since it uses as much as digits as its factorization.

61613431106681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 373248, while the sum is 47.

The spelling of 61613431106681 in words is "sixty-one trillion, six hundred thirteen billion, four hundred thirty-one million, one hundred six thousand, six hundred eighty-one".