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621421512433 is a prime number
BaseRepresentation
bin10010000101011111001…
…10111100011011110001
32012101222221012122012121
421002233212330123301
540140132401344213
61153251015354241
762616255463021
oct11025746743361
92171887178177
10621421512433
1121a5a8274987
12a0528982981
13467a49a6557
142211127ba81
15112707cc88d
hex90af9bc6f1

621421512433 has 2 divisors, whose sum is σ = 621421512434. Its totient is φ = 621421512432.

The previous prime is 621421512431. The next prime is 621421512461. The reversal of 621421512433 is 334215124126.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 440905296049 + 180516216384 = 664007^2 + 424872^2 .

It is a cyclic number.

It is not a de Polignac number, because 621421512433 - 21 = 621421512431 is a prime.

It is a super-2 number, since 2×6214215124332 (a number of 24 digits) contains 22 as substring.

Together with 621421512431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (621421512431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310710756216 + 310710756217.

It is an arithmetic number, because the mean of its divisors is an integer number (310710756217).

Almost surely, 2621421512433 is an apocalyptic number.

It is an amenable number.

621421512433 is a deficient number, since it is larger than the sum of its proper divisors (1).

621421512433 is an equidigital number, since it uses as much as digits as its factorization.

621421512433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 34.

Adding to 621421512433 its reverse (334215124126), we get a palindrome (955636636559).

The spelling of 621421512433 in words is "six hundred twenty-one billion, four hundred twenty-one million, five hundred twelve thousand, four hundred thirty-three".