Base | Representation |
---|---|
bin | 11100110000010001011000… |
… | …11001011101100111110101 |
3 | 22021212211220202201220112202 |
4 | 32120020230121131213311 |
5 | 31241440101332413044 |
6 | 342252011540554245 |
7 | 16214210255620055 |
oct | 1630105431354765 |
9 | 267784822656482 |
10 | 63231253404149 |
11 | 19169251125106 |
12 | 71127829b2985 |
13 | 29388b26647bc |
14 | 11885a23cb565 |
15 | 749bcb42dc4e |
hex | 39822c65d9f5 |
63231253404149 has 2 divisors, whose sum is σ = 63231253404150. Its totient is φ = 63231253404148.
The previous prime is 63231253404107. The next prime is 63231253404173. The reversal of 63231253404149 is 94140435213236.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50621545873924 + 12609707530225 = 7114882^2 + 3551015^2 .
It is a cyclic number.
It is not a de Polignac number, because 63231253404149 - 236 = 63162533927413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (63231253407149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31615626702074 + 31615626702075.
It is an arithmetic number, because the mean of its divisors is an integer number (31615626702075).
Almost surely, 263231253404149 is an apocalyptic number.
It is an amenable number.
63231253404149 is a deficient number, since it is larger than the sum of its proper divisors (1).
63231253404149 is an equidigital number, since it uses as much as digits as its factorization.
63231253404149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 47.
The spelling of 63231253404149 in words is "sixty-three trillion, two hundred thirty-one billion, two hundred fifty-three million, four hundred four thousand, one hundred forty-nine".
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