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63314252717 is a prime number
BaseRepresentation
bin111010111101110100…
…101101001110101101
320001102110221021202212
4322331310231032231
52014131422041332
645030340100205
74400662161032
oct727564551655
9201373837685
1063314252717
11249402771a1
121032b994665
135c8028c981
1430c8add389
1519a86bd8b2
hexebdd2d3ad

63314252717 has 2 divisors, whose sum is σ = 63314252718. Its totient is φ = 63314252716.

The previous prime is 63314252713. The next prime is 63314252761. The reversal of 63314252717 is 71725241336.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48976345636 + 14337907081 = 221306^2 + 119741^2 .

It is a cyclic number.

It is not a de Polignac number, because 63314252717 - 22 = 63314252713 is a prime.

It is a super-2 number, since 2×633142527172 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (63314252713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31657126358 + 31657126359.

It is an arithmetic number, because the mean of its divisors is an integer number (31657126359).

Almost surely, 263314252717 is an apocalyptic number.

It is an amenable number.

63314252717 is a deficient number, since it is larger than the sum of its proper divisors (1).

63314252717 is an equidigital number, since it uses as much as digits as its factorization.

63314252717 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 211680, while the sum is 41.

The spelling of 63314252717 in words is "sixty-three billion, three hundred fourteen million, two hundred fifty-two thousand, seven hundred seventeen".