Base | Representation |
---|---|
bin | 1001000001000000110100010… |
… | …1000010111111010011100101 |
3 | 10002012100010112111200210122202 |
4 | 2100100031011002333103211 |
5 | 1131124014223122241013 |
6 | 10125154053033504245 |
7 | 250430134435635665 |
oct | 22020150502772345 |
9 | 3065303474623582 |
10 | 634432252540133 |
11 | 174171230a42803 |
12 | 5b1a5279872085 |
13 | 213009213139b8 |
14 | b29498339c1a5 |
15 | 4d5308b0bd858 |
hex | 24103450bf4e5 |
634432252540133 has 2 divisors, whose sum is σ = 634432252540134. Its totient is φ = 634432252540132.
The previous prime is 634432252540127. The next prime is 634432252540169. The reversal of 634432252540133 is 331045252234436.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 634415294510404 + 16958029729 = 25187602^2 + 130223^2 .
It is a cyclic number.
It is not a de Polignac number, because 634432252540133 - 210 = 634432252539109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (634432252540633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 317216126270066 + 317216126270067.
It is an arithmetic number, because the mean of its divisors is an integer number (317216126270067).
Almost surely, 2634432252540133 is an apocalyptic number.
It is an amenable number.
634432252540133 is a deficient number, since it is larger than the sum of its proper divisors (1).
634432252540133 is an equidigital number, since it uses as much as digits as its factorization.
634432252540133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6220800, while the sum is 47.
The spelling of 634432252540133 in words is "six hundred thirty-four trillion, four hundred thirty-two billion, two hundred fifty-two million, five hundred forty thousand, one hundred thirty-three".
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