Base | Representation |
---|---|
bin | 11100111000010011010000… |
… | …01100000000010100001110 |
3 | 22022212020000101112101201202 |
4 | 32130021220030000110032 |
5 | 31311000102402304032 |
6 | 343022435204305502 |
7 | 16243144664544224 |
oct | 1634115014002416 |
9 | 268766011471652 |
10 | 63507134416142 |
11 | 1926525182876a |
12 | 71581369a2292 |
13 | 295890a635971 |
14 | 1197a9419cb14 |
15 | 751e76445d62 |
hex | 39c26830050e |
63507134416142 has 4 divisors (see below), whose sum is σ = 95260701624216. Its totient is φ = 31753567208070.
The previous prime is 63507134416123. The next prime is 63507134416177. The reversal of 63507134416142 is 24161443170536.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×635071344161422 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15876783604034 + ... + 15876783604037.
It is an arithmetic number, because the mean of its divisors is an integer number (23815175406054).
Almost surely, 263507134416142 is an apocalyptic number.
63507134416142 is a deficient number, since it is larger than the sum of its proper divisors (31753567208074).
63507134416142 is a wasteful number, since it uses less digits than its factorization.
63507134416142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31753567208073.
The product of its (nonzero) digits is 1451520, while the sum is 47.
Adding to 63507134416142 its reverse (24161443170536), we get a palindrome (87668577586678).
The spelling of 63507134416142 in words is "sixty-three trillion, five hundred seven billion, one hundred thirty-four million, four hundred sixteen thousand, one hundred forty-two".
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