Base | Representation |
---|---|
bin | 100110000101101… |
… | …001100110101101 |
3 | 1122112102100020212 |
4 | 212011221212231 |
5 | 2302041442331 |
6 | 143224152205 |
7 | 21556353326 |
oct | 4605514655 |
9 | 1575370225 |
10 | 639015341 |
11 | 2a8786758 |
12 | 15a008665 |
13 | a25091b3 |
14 | 60c2144d |
15 | 3b177d2b |
hex | 261699ad |
639015341 has 2 divisors, whose sum is σ = 639015342. Its totient is φ = 639015340.
The previous prime is 639015317. The next prime is 639015409. The reversal of 639015341 is 143510936.
639015341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 577392841 + 61622500 = 24029^2 + 7850^2 .
It is a cyclic number.
It is not a de Polignac number, because 639015341 - 210 = 639014317 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 639015298 and 639015307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (639015241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 319507670 + 319507671.
It is an arithmetic number, because the mean of its divisors is an integer number (319507671).
Almost surely, 2639015341 is an apocalyptic number.
It is an amenable number.
639015341 is a deficient number, since it is larger than the sum of its proper divisors (1).
639015341 is an equidigital number, since it uses as much as digits as its factorization.
639015341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 32.
The square root of 639015341 is about 25278.7527579982. The cubic root of 639015341 is about 861.3316942679.
The spelling of 639015341 in words is "six hundred thirty-nine million, fifteen thousand, three hundred forty-one".
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