Base | Representation |
---|---|
bin | 111011100110101111… |
… | …001010110111101001 |
3 | 20010012022112202022021 |
4 | 323212233022313221 |
5 | 2022033132321423 |
6 | 45222420224441 |
7 | 4423665460135 |
oct | 734657126751 |
9 | 203168482267 |
10 | 64000667113 |
11 | 25162787519 |
12 | 104a183b121 |
13 | 605c553436 |
14 | 3151d3c3c5 |
15 | 19e8aaa95d |
hex | ee6bcade9 |
64000667113 has 2 divisors, whose sum is σ = 64000667114. Its totient is φ = 64000667112.
The previous prime is 64000667111. The next prime is 64000667177. The reversal of 64000667113 is 31176600046.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58972722649 + 5027944464 = 242843^2 + 70908^2 .
It is a cyclic number.
It is not a de Polignac number, because 64000667113 - 21 = 64000667111 is a prime.
Together with 64000667111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (64000667111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32000333556 + 32000333557.
It is an arithmetic number, because the mean of its divisors is an integer number (32000333557).
Almost surely, 264000667113 is an apocalyptic number.
It is an amenable number.
64000667113 is a deficient number, since it is larger than the sum of its proper divisors (1).
64000667113 is an equidigital number, since it uses as much as digits as its factorization.
64000667113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 34.
The spelling of 64000667113 in words is "sixty-four billion, six hundred sixty-seven thousand, one hundred thirteen".
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