Base | Representation |
---|---|
bin | 111011100110110110… |
… | …111001000000111101 |
3 | 20010012110100120201222 |
4 | 323212312321000331 |
5 | 2022034142104013 |
6 | 45222531443125 |
7 | 4424021620103 |
oct | 734666710075 |
9 | 203173316658 |
10 | 64002691133 |
11 | 2516393a167 |
12 | 104a24564a5 |
13 | 605cab1794 |
14 | 3152307c73 |
15 | 19e8d5a508 |
hex | ee6db903d |
64002691133 has 2 divisors, whose sum is σ = 64002691134. Its totient is φ = 64002691132.
The previous prime is 64002691021. The next prime is 64002691139. The reversal of 64002691133 is 33119620046.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42369282244 + 21633408889 = 205838^2 + 147083^2 .
It is a cyclic number.
It is not a de Polignac number, because 64002691133 - 210 = 64002690109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 64002691093 and 64002691102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64002691139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32001345566 + 32001345567.
It is an arithmetic number, because the mean of its divisors is an integer number (32001345567).
Almost surely, 264002691133 is an apocalyptic number.
It is an amenable number.
64002691133 is a deficient number, since it is larger than the sum of its proper divisors (1).
64002691133 is an equidigital number, since it uses as much as digits as its factorization.
64002691133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 64002691133 in words is "sixty-four billion, two million, six hundred ninety-one thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •