Base | Representation |
---|---|
bin | 11101000110101110011011… |
… | …00001010001110001000111 |
3 | 22101121121022002110211111002 |
4 | 32203113031201101301013 |
5 | 31342110120431334003 |
6 | 344042243213203515 |
7 | 16324021644320342 |
oct | 1643271541216107 |
9 | 271547262424432 |
10 | 64002755730503 |
11 | 194364640748a7 |
12 | 72181b549059b |
13 | 2993584574195 |
14 | 11b3a6da55459 |
15 | 75ecd2950a88 |
hex | 3a35cd851c47 |
64002755730503 has 2 divisors, whose sum is σ = 64002755730504. Its totient is φ = 64002755730502.
The previous prime is 64002755730457. The next prime is 64002755730523. The reversal of 64002755730503 is 30503755720046.
64002755730503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64002755730503 - 28 = 64002755730247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64002755730523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32001377865251 + 32001377865252.
It is an arithmetic number, because the mean of its divisors is an integer number (32001377865252).
Almost surely, 264002755730503 is an apocalyptic number.
64002755730503 is a deficient number, since it is larger than the sum of its proper divisors (1).
64002755730503 is an equidigital number, since it uses as much as digits as its factorization.
64002755730503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2646000, while the sum is 47.
The spelling of 64002755730503 in words is "sixty-four trillion, two billion, seven hundred fifty-five million, seven hundred thirty thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •