Base | Representation |
---|---|
bin | 101110100100110010101… |
… | …0101101011000100101111 |
3 | 211122221121201211222020202 |
4 | 1131021211111223010233 |
5 | 1314334130032420221 |
6 | 21340401002304115 |
7 | 1230320511403532 |
oct | 135114525530457 |
9 | 24587551758222 |
10 | 6401201451311 |
11 | 2048809381a17 |
12 | 8747194b803b |
13 | 375827880074 |
14 | 181b6977ca19 |
15 | b179b0a6d0b |
hex | 5d26556b12f |
6401201451311 has 2 divisors, whose sum is σ = 6401201451312. Its totient is φ = 6401201451310.
The previous prime is 6401201451301. The next prime is 6401201451313. The reversal of 6401201451311 is 1131541021046.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6401201451311 - 218 = 6401201189167 is a prime.
Together with 6401201451313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6401201451313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3200600725655 + 3200600725656.
It is an arithmetic number, because the mean of its divisors is an integer number (3200600725656).
Almost surely, 26401201451311 is an apocalyptic number.
6401201451311 is a deficient number, since it is larger than the sum of its proper divisors (1).
6401201451311 is an equidigital number, since it uses as much as digits as its factorization.
6401201451311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 6401201451311 its reverse (1131541021046), we get a palindrome (7532742472357).
The spelling of 6401201451311 in words is "six trillion, four hundred one billion, two hundred one million, four hundred fifty-one thousand, three hundred eleven".
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