Base | Representation |
---|---|
bin | 10010101010000001000… |
… | …01000101011010110111 |
3 | 2021021121122211011011112 |
4 | 21111000201011122313 |
5 | 41000313312320004 |
6 | 1210253012025235 |
7 | 64212245463002 |
oct | 11250041053267 |
9 | 2237548734145 |
10 | 641032541879 |
11 | 227951181634 |
12 | a42a060221b |
13 | 485ab901ba2 |
14 | 23051a30539 |
15 | 11a1c312e6e |
hex | 95408456b7 |
641032541879 has 2 divisors, whose sum is σ = 641032541880. Its totient is φ = 641032541878.
The previous prime is 641032541813. The next prime is 641032541917. The reversal of 641032541879 is 978145230146.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 641032541879 - 220 = 641031493303 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (641032541179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320516270939 + 320516270940.
It is an arithmetic number, because the mean of its divisors is an integer number (320516270940).
It is a 1-persistent number, because it is pandigital, but 2⋅641032541879 = 1282065083758 is not.
Almost surely, 2641032541879 is an apocalyptic number.
641032541879 is a deficient number, since it is larger than the sum of its proper divisors (1).
641032541879 is an equidigital number, since it uses as much as digits as its factorization.
641032541879 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 50.
The spelling of 641032541879 in words is "six hundred forty-one billion, thirty-two million, five hundred forty-one thousand, eight hundred seventy-nine".
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