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641095066693 is a prime number
BaseRepresentation
bin10010101010001000011…
…11100110010001000101
32021021210000110202002101
421111010033212101011
541000430314113233
61210303124112101
764213635104044
oct11250417462105
92237700422071
10641095066693
112279834a7434
12a42b9535631
13485bb854113
142305a06855b
1511a22a63c7d
hex95443e6445

641095066693 has 2 divisors, whose sum is σ = 641095066694. Its totient is φ = 641095066692.

The previous prime is 641095066691. The next prime is 641095066697. The reversal of 641095066693 is 396660590146.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 497338069284 + 143756997409 = 705222^2 + 379153^2 .

It is a cyclic number.

It is not a de Polignac number, because 641095066693 - 21 = 641095066691 is a prime.

It is a super-3 number, since 3×6410950666933 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 641095066691, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641095066691) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320547533346 + 320547533347.

It is an arithmetic number, because the mean of its divisors is an integer number (320547533347).

Almost surely, 2641095066693 is an apocalyptic number.

It is an amenable number.

641095066693 is a deficient number, since it is larger than the sum of its proper divisors (1).

641095066693 is an equidigital number, since it uses as much as digits as its factorization.

641095066693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6298560, while the sum is 55.

The spelling of 641095066693 in words is "six hundred forty-one billion, ninety-five million, sixty-six thousand, six hundred ninety-three".