Search a number
-
+
64110409860437 is a prime number
BaseRepresentation
bin11101001001110110111100…
…01101001100010101010101
322101222220011200201021002122
432210323132031030111111
531400341104411013222
6344203525442545325
716334552502322433
oct1644733615142525
9271886150637078
1064110409860437
1119478088014016
12723503a668245
1329a077ca58595
1411b8d63469d53
157629d3b15a42
hex3a4ede34c555

64110409860437 has 2 divisors, whose sum is σ = 64110409860438. Its totient is φ = 64110409860436.

The previous prime is 64110409860403. The next prime is 64110409860479. The reversal of 64110409860437 is 73406890401146.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48424326820081 + 15686083040356 = 6958759^2 + 3960566^2 .

It is a cyclic number.

It is not a de Polignac number, because 64110409860437 - 222 = 64110405666133 is a prime.

It is a super-2 number, since 2×641104098604372 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64110408860437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32055204930218 + 32055204930219.

It is an arithmetic number, because the mean of its divisors is an integer number (32055204930219).

Almost surely, 264110409860437 is an apocalyptic number.

It is an amenable number.

64110409860437 is a deficient number, since it is larger than the sum of its proper divisors (1).

64110409860437 is an equidigital number, since it uses as much as digits as its factorization.

64110409860437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3483648, while the sum is 53.

The spelling of 64110409860437 in words is "sixty-four trillion, one hundred ten billion, four hundred nine million, eight hundred sixty thousand, four hundred thirty-seven".