Base | Representation |
---|---|
bin | 10010101010010011000… |
… | …01101010100100101111 |
3 | 2021022000012020020001022 |
4 | 21111021201222210233 |
5 | 41001121011022012 |
6 | 1210320011404355 |
7 | 64216062301121 |
oct | 11251141524457 |
9 | 2238005206038 |
10 | 641183689007 |
11 | 227a19527714 |
12 | a43231536bb |
13 | 48604012c64 |
14 | 23067b37211 |
15 | 11a2a71c472 |
hex | 954986a92f |
641183689007 has 2 divisors, whose sum is σ = 641183689008. Its totient is φ = 641183689006.
The previous prime is 641183688989. The next prime is 641183689019. The reversal of 641183689007 is 700986381146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 641183689007 - 28 = 641183688751 is a prime.
It is a super-2 number, since 2×6411836890072 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 641183689007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (641183689067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320591844503 + 320591844504.
It is an arithmetic number, because the mean of its divisors is an integer number (320591844504).
Almost surely, 2641183689007 is an apocalyptic number.
641183689007 is a deficient number, since it is larger than the sum of its proper divisors (1).
641183689007 is an equidigital number, since it uses as much as digits as its factorization.
641183689007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1741824, while the sum is 53.
The spelling of 641183689007 in words is "six hundred forty-one billion, one hundred eighty-three million, six hundred eighty-nine thousand, seven".
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