64123938881 has 2 divisors, whose sum is σ = 64123938882. Its totient is φ = 64123938880.

The previous prime is 64123938871. The next prime is 64123938883. The reversal of 64123938881 is 18883932146.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61682689600 + 2441249281 = 248360^2 + 49409^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-64123938881 is a prime.

It is a super-2 number, since 2×64123938881² (a number of 22 digits) contains 22 as substring.

Together with 64123938883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (64123938883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32061969440 + 32061969441.

It is an arithmetic number, because the mean of its divisors is an integer number (32061969441).

Almost surely, 2^64123938881 is an apocalyptic number.

It is an amenable number.

64123938881 is a deficient number, since it is larger than the sum of its proper divisors (1).

64123938881 is an equidigital number, since it uses as much as digits as its factorization.

64123938881 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1990656, while the sum is 53.

The spelling of 64123938881 in words is "sixty-four billion, one hundred twenty-three million, nine hundred thirty-eight thousand, eight hundred eighty-one".