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641460554807 is a prime number
BaseRepresentation
bin10010101010110100000…
…01110100110000110111
32021022201111012110112012
421111122001310300313
541002202400223212
61210403301514435
764225663516052
oct11253201646067
92238644173465
10641460554807
11228050840026
12a439ba12a1b
13486494a0b87
1423092807a99
1511a44bab922
hex955a074c37

641460554807 has 2 divisors, whose sum is σ = 641460554808. Its totient is φ = 641460554806.

The previous prime is 641460554767. The next prime is 641460554809. The reversal of 641460554807 is 708455064146.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 641460554807 - 238 = 366582647863 is a prime.

It is a super-2 number, since 2×6414605548072 (a number of 24 digits) contains 22 as substring.

Together with 641460554809, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641460554809) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320730277403 + 320730277404.

It is an arithmetic number, because the mean of its divisors is an integer number (320730277404).

Almost surely, 2641460554807 is an apocalyptic number.

641460554807 is a deficient number, since it is larger than the sum of its proper divisors (1).

641460554807 is an equidigital number, since it uses as much as digits as its factorization.

641460554807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3225600, while the sum is 50.

The spelling of 641460554807 in words is "six hundred forty-one billion, four hundred sixty million, five hundred fifty-four thousand, eight hundred seven".