Base | Representation |
---|---|
bin | 111011110000000100… |
… | …000000000010111111 |
3 | 20010121012221112002112 |
4 | 323300010000002333 |
5 | 2022343210412001 |
6 | 45250125444235 |
7 | 4430605355051 |
oct | 736004000277 |
9 | 203535845075 |
10 | 64157122751 |
11 | 252330289a7 |
12 | 1052611067b |
13 | 6085aa2837 |
14 | 3168a278d1 |
15 | 1a076b2cbb |
hex | ef01000bf |
64157122751 has 2 divisors, whose sum is σ = 64157122752. Its totient is φ = 64157122750.
The previous prime is 64157122739. The next prime is 64157122753. The reversal of 64157122751 is 15722175146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64157122751 - 226 = 64090013887 is a prime.
It is a super-2 number, since 2×641571227512 (a number of 22 digits) contains 22 as substring.
Together with 64157122753, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 64157122699 and 64157122708.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64157122753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32078561375 + 32078561376.
It is an arithmetic number, because the mean of its divisors is an integer number (32078561376).
Almost surely, 264157122751 is an apocalyptic number.
64157122751 is a deficient number, since it is larger than the sum of its proper divisors (1).
64157122751 is an equidigital number, since it uses as much as digits as its factorization.
64157122751 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 117600, while the sum is 41.
Adding to 64157122751 its reverse (15722175146), we get a palindrome (79879297897).
The spelling of 64157122751 in words is "sixty-four billion, one hundred fifty-seven million, one hundred twenty-two thousand, seven hundred fifty-one".
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