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643310012069 is a prime number
BaseRepresentation
bin10010101110010000100…
…00111100011010100101
32021111111101021121221022
421113020100330122211
541014444330341234
61211311010100525
764322551610534
oct11271020743245
92244441247838
10643310012069
1122890a8046aa
12a481727a745
13488826b929a
14231ca2b631b
1511b02233e2e
hex95c843c6a5

643310012069 has 2 divisors, whose sum is σ = 643310012070. Its totient is φ = 643310012068.

The previous prime is 643310011973. The next prime is 643310012099. The reversal of 643310012069 is 960210013346.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 584365455844 + 58944556225 = 764438^2 + 242785^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-643310012069 is a prime.

It is a super-2 number, since 2×6433100120692 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (643310012099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321655006034 + 321655006035.

It is an arithmetic number, because the mean of its divisors is an integer number (321655006035).

Almost surely, 2643310012069 is an apocalyptic number.

It is an amenable number.

643310012069 is a deficient number, since it is larger than the sum of its proper divisors (1).

643310012069 is an equidigital number, since it uses as much as digits as its factorization.

643310012069 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 643310012069 in words is "six hundred forty-three billion, three hundred ten million, twelve thousand, sixty-nine".