Base | Representation |
---|---|
bin | 1111010101100… |
… | …1111001011101 |
3 | 11111001101000212 |
4 | 3311121321131 |
5 | 112432100412 |
6 | 10214502205 |
7 | 1410543656 |
oct | 365317135 |
9 | 144041025 |
10 | 64331357 |
11 | 3334a112 |
12 | 19664965 |
13 | 104355bc |
14 | 878852d |
15 | 59ab222 |
hex | 3d59e5d |
64331357 has 2 divisors, whose sum is σ = 64331358. Its totient is φ = 64331356.
The previous prime is 64331341. The next prime is 64331363. The reversal of 64331357 is 75313346.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64176121 + 155236 = 8011^2 + 394^2 .
It is a cyclic number.
It is not a de Polignac number, because 64331357 - 24 = 64331341 is a prime.
It is a super-2 number, since 2×643313572 = 8277046986922898, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64331317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32165678 + 32165679.
It is an arithmetic number, because the mean of its divisors is an integer number (32165679).
Almost surely, 264331357 is an apocalyptic number.
It is an amenable number.
64331357 is a deficient number, since it is larger than the sum of its proper divisors (1).
64331357 is an equidigital number, since it uses as much as digits as its factorization.
64331357 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 22680, while the sum is 32.
The square root of 64331357 is about 8020.6830756489. The cubic root of 64331357 is about 400.6891391197.
The spelling of 64331357 in words is "sixty-four million, three hundred thirty-one thousand, three hundred fifty-seven".
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