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645540646133 is a prime number
BaseRepresentation
bin10010110010011010011…
…10001000110011110101
32021201020211121120121202
421121031032020303311
541034031401134013
61212320212222245
764432045646045
oct11311516106365
92251224546552
10645540646133
11229854958029
12a513a30a985
1348b498853b6
142335c649725
1511bd2ea2858
hex964d388cf5

645540646133 has 2 divisors, whose sum is σ = 645540646134. Its totient is φ = 645540646132.

The previous prime is 645540646109. The next prime is 645540646171. The reversal of 645540646133 is 331646045546.

645540646133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 377773724689 + 267766921444 = 614633^2 + 517462^2 .

It is a cyclic number.

It is not a de Polignac number, because 645540646133 - 28 = 645540645877 is a prime.

It is a super-2 number, since 2×6455406461332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (645540646183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 322770323066 + 322770323067.

It is an arithmetic number, because the mean of its divisors is an integer number (322770323067).

Almost surely, 2645540646133 is an apocalyptic number.

It is an amenable number.

645540646133 is a deficient number, since it is larger than the sum of its proper divisors (1).

645540646133 is an equidigital number, since it uses as much as digits as its factorization.

645540646133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3110400, while the sum is 47.

The spelling of 645540646133 in words is "six hundred forty-five billion, five hundred forty million, six hundred forty-six thousand, one hundred thirty-three".