Search a number
-
+
649049741 is a prime number
BaseRepresentation
bin100110101011111…
…011011010001101
31200020022010212022
4212223323122031
52312124042431
6144223215525
722040555204
oct4653733215
91606263768
10649049741
1130340a74a
121614475a5
13a4610602
14622b423b
153beab07b
hex26afb68d

649049741 has 2 divisors, whose sum is σ = 649049742. Its totient is φ = 649049740.

The previous prime is 649049669. The next prime is 649049813. The reversal of 649049741 is 147940946.

It is a balanced prime because it is at equal distance from previous prime (649049669) and next prime (649049813).

It can be written as a sum of positive squares in only one way, i.e., 573794116 + 75255625 = 23954^2 + 8675^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-649049741 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 649049692 and 649049701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (649049441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 324524870 + 324524871.

It is an arithmetic number, because the mean of its divisors is an integer number (324524871).

Almost surely, 2649049741 is an apocalyptic number.

It is an amenable number.

649049741 is a deficient number, since it is larger than the sum of its proper divisors (1).

649049741 is an equidigital number, since it uses as much as digits as its factorization.

649049741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 44.

The square root of 649049741 is about 25476.4546395294. The cubic root of 649049741 is about 865.8167704876.

The spelling of 649049741 in words is "six hundred forty-nine million, forty-nine thousand, seven hundred forty-one".