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6513545343317 is a prime number
BaseRepresentation
bin101111011001000110110…
…0011100111000101010101
3212001200121011200222222212
41132302031203213011111
51323204220101441232
621504140442003205
71241405503623425
oct136621543470525
925050534628885
106513545343317
1120914195a1861
128924511a6505
133832bc84c2cc
14187385d78485
15b4673d40eb2
hex5ec8d8e7155

6513545343317 has 2 divisors, whose sum is σ = 6513545343318. Its totient is φ = 6513545343316.

The previous prime is 6513545343293. The next prime is 6513545343323. The reversal of 6513545343317 is 7133435453156.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3868778220241 + 2644767123076 = 1966921^2 + 1626274^2 .

It is a cyclic number.

It is not a de Polignac number, because 6513545343317 - 28 = 6513545343061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6513545343397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3256772671658 + 3256772671659.

It is an arithmetic number, because the mean of its divisors is an integer number (3256772671659).

Almost surely, 26513545343317 is an apocalyptic number.

It is an amenable number.

6513545343317 is a deficient number, since it is larger than the sum of its proper divisors (1).

6513545343317 is an equidigital number, since it uses as much as digits as its factorization.

6513545343317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6804000, while the sum is 50.

The spelling of 6513545343317 in words is "six trillion, five hundred thirteen billion, five hundred forty-five million, three hundred forty-three thousand, three hundred seventeen".