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653614124213 is a prime number
BaseRepresentation
bin10011000001011100111…
…00000000110010110101
32022111002111021202111102
421200232130000302311
541202100203433323
61220133255015445
765136111250031
oct11405634006265
92274074252442
10653614124213
11232218151666
12a681206a585
13498353b416b
14238c699d1c1
1512006b64328
hex982e700cb5

653614124213 has 2 divisors, whose sum is σ = 653614124214. Its totient is φ = 653614124212.

The previous prime is 653614124183. The next prime is 653614124221. The reversal of 653614124213 is 312421416356.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 387851191729 + 265762932484 = 622777^2 + 515522^2 .

It is a cyclic number.

It is not a de Polignac number, because 653614124213 - 222 = 653609929909 is a prime.

It is a super-2 number, since 2×6536141242132 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (653614124243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326807062106 + 326807062107.

It is an arithmetic number, because the mean of its divisors is an integer number (326807062107).

Almost surely, 2653614124213 is an apocalyptic number.

It is an amenable number.

653614124213 is a deficient number, since it is larger than the sum of its proper divisors (1).

653614124213 is an equidigital number, since it uses as much as digits as its factorization.

653614124213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 38.

The spelling of 653614124213 in words is "six hundred fifty-three billion, six hundred fourteen million, one hundred twenty-four thousand, two hundred thirteen".