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65431922681 is a prime number
BaseRepresentation
bin111100111100000010…
…111110011111111001
320020220001201001211202
4330330002332133321
52033001033011211
650020425103545
74504315110656
oct747402763771
9206801631752
1065431922681
1125827683a64
1210821027bb5
136229c26518
14324a068c2d
151a7e57653b
hexf3c0be7f9

65431922681 has 2 divisors, whose sum is σ = 65431922682. Its totient is φ = 65431922680.

The previous prime is 65431922671. The next prime is 65431922683. The reversal of 65431922681 is 18622913456.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36382129081 + 29049793600 = 190741^2 + 170440^2 .

It is a cyclic number.

It is not a de Polignac number, because 65431922681 - 230 = 64358180857 is a prime.

It is a super-2 number, since 2×654319226812 (a number of 22 digits) contains 22 as substring.

Together with 65431922683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (65431922683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32715961340 + 32715961341.

It is an arithmetic number, because the mean of its divisors is an integer number (32715961341).

Almost surely, 265431922681 is an apocalyptic number.

It is an amenable number.

65431922681 is a deficient number, since it is larger than the sum of its proper divisors (1).

65431922681 is an equidigital number, since it uses as much as digits as its factorization.

65431922681 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 622080, while the sum is 47.

The spelling of 65431922681 in words is "sixty-five billion, four hundred thirty-one million, nine hundred twenty-two thousand, six hundred eighty-one".