Search a number
-
+
662002435991653 is a prime number
BaseRepresentation
bin1001011010000101100111010…
…0000010011010100001100101
310012210221210222222212201222121
42112201121310002122201211
51143232221442103213103
610303543415355425541
7256304045332422301
oct22641316402324145
93183853888781877
10662002435991653
11181a30724827479
12622b86104552b1
132255073c4ca353
14b969135ba2d01
155180308a336bd
hex25a167409a865

662002435991653 has 2 divisors, whose sum is σ = 662002435991654. Its totient is φ = 662002435991652.

The previous prime is 662002435991651. The next prime is 662002435991671. The reversal of 662002435991653 is 356199534200266.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 546783722927649 + 115218713064004 = 23383407^2 + 10733998^2 .

It is a cyclic number.

It is not a de Polignac number, because 662002435991653 - 21 = 662002435991651 is a prime.

Together with 662002435991651, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 662002435991591 and 662002435991600.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (662002435991651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 331001217995826 + 331001217995827.

It is an arithmetic number, because the mean of its divisors is an integer number (331001217995827).

Almost surely, 2662002435991653 is an apocalyptic number.

It is an amenable number.

662002435991653 is a deficient number, since it is larger than the sum of its proper divisors (1).

662002435991653 is an equidigital number, since it uses as much as digits as its factorization.

662002435991653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62985600, while the sum is 61.

The spelling of 662002435991653 in words is "six hundred sixty-two trillion, two billion, four hundred thirty-five million, nine hundred ninety-one thousand, six hundred fifty-three".