Base | Representation |
---|---|
bin | 110000011101100010101… |
… | …1001010110010100111111 |
3 | 212120201221110122020002002 |
4 | 1200323011121112110333 |
5 | 1333111211313043112 |
6 | 22055444015252515 |
7 | 1255130446635413 |
oct | 140730531262477 |
9 | 25521843566062 |
10 | 6660511065407 |
11 | 2138785948011 |
12 | 8b6a2781a13b |
13 | 3941115a5044 |
14 | 19052875cd43 |
15 | b83c635a1c2 |
hex | 60ec565653f |
6660511065407 has 2 divisors, whose sum is σ = 6660511065408. Its totient is φ = 6660511065406.
The previous prime is 6660511065319. The next prime is 6660511065473. The reversal of 6660511065407 is 7045601150666.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6660511065407 - 224 = 6660494288191 is a prime.
It is a super-3 number, since 3×66605110654073 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6660511965407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330255532703 + 3330255532704.
It is an arithmetic number, because the mean of its divisors is an integer number (3330255532704).
Almost surely, 26660511065407 is an apocalyptic number.
6660511065407 is a deficient number, since it is larger than the sum of its proper divisors (1).
6660511065407 is an equidigital number, since it uses as much as digits as its factorization.
6660511065407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 47.
The spelling of 6660511065407 in words is "six trillion, six hundred sixty billion, five hundred eleven million, sixty-five thousand, four hundred seven".
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