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67314253241 is a prime number
BaseRepresentation
bin111110101100001111…
…011111110110111001
320102202020122100221102
4332230033133312321
52100324422100431
650531310021145
74602052466114
oct765417376671
9212666570842
1067314253241
1126603160854
12110674a77b5
136469bb16a1
14338805357b
151b3e943dcb
hexfac3dfdb9

67314253241 has 2 divisors, whose sum is σ = 67314253242. Its totient is φ = 67314253240.

The previous prime is 67314253229. The next prime is 67314253243. The reversal of 67314253241 is 14235241376.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66396405625 + 917847616 = 257675^2 + 30296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-67314253241 is a prime.

It is a Sophie Germain prime.

Together with 67314253243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 67314253195 and 67314253204.

It is not a weakly prime, because it can be changed into another prime (67314253243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33657126620 + 33657126621.

It is an arithmetic number, because the mean of its divisors is an integer number (33657126621).

Almost surely, 267314253241 is an apocalyptic number.

It is an amenable number.

67314253241 is a deficient number, since it is larger than the sum of its proper divisors (1).

67314253241 is an equidigital number, since it uses as much as digits as its factorization.

67314253241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 38.

The spelling of 67314253241 in words is "sixty-seven billion, three hundred fourteen million, two hundred fifty-three thousand, two hundred forty-one".