Base | Representation |
---|---|
bin | 110001100011000110010… |
… | …0111010111101001001111 |
3 | 220010000111101221212220201 |
4 | 1203012030213113221033 |
5 | 1343033114331413423 |
6 | 22252230003154331 |
7 | 1301666142302404 |
oct | 143061447275117 |
9 | 26100441855821 |
10 | 6809882294863 |
11 | 219606702758a |
12 | 91b9739759a7 |
13 | 3a52277c440b |
14 | 1978587d82ab |
15 | bc219b372ad |
hex | 6318c9d7a4f |
6809882294863 has 2 divisors, whose sum is σ = 6809882294864. Its totient is φ = 6809882294862.
The previous prime is 6809882294827. The next prime is 6809882294899. The reversal of 6809882294863 is 3684922889086.
6809882294863 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (6809882294827) and next prime (6809882294899).
It is a cyclic number.
It is not a de Polignac number, because 6809882294863 - 213 = 6809882286671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6809882294563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3404941147431 + 3404941147432.
It is an arithmetic number, because the mean of its divisors is an integer number (3404941147432).
Almost surely, 26809882294863 is an apocalyptic number.
6809882294863 is a deficient number, since it is larger than the sum of its proper divisors (1).
6809882294863 is an equidigital number, since it uses as much as digits as its factorization.
6809882294863 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 573308928, while the sum is 73.
The spelling of 6809882294863 in words is "six trillion, eight hundred nine billion, eight hundred eighty-two million, two hundred ninety-four thousand, eight hundred sixty-three".
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