68107254893 has 2 divisors, whose sum is σ = 68107254894. Its totient is φ = 68107254892.

The previous prime is 68107254871. The next prime is 68107254911. The reversal of 68107254893 is 39845270186.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37186494244 + 30920760649 = 192838^2 + 175843^2 .

It is a cyclic number.

It is not a de Polignac number, because 68107254893 - 2⁸ = 68107254637 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is a weakly prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34053627446 + 34053627447.

It is an arithmetic number, because the mean of its divisors is an integer number (34053627447).

It is a 2-persistent number, because it is pandigital, and so is 2⋅68107254893 = 136214509786, but 3⋅68107254893 = 204321764679 is not.

Almost surely, 2^68107254893 is an apocalyptic number.

It is an amenable number.

68107254893 is a deficient number, since it is larger than the sum of its proper divisors (1).

68107254893 is an equidigital number, since it uses as much as digits as its factorization.

68107254893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 68107254893 in words is "sixty-eight billion, one hundred seven million, two hundred fifty-four thousand, eight hundred ninety-three".