Base | Representation |
---|---|
bin | 1100101011111011… |
… | …11100100000111101 |
3 | 122120200010012210121 |
4 | 12111331330200331 |
5 | 102422104324013 |
6 | 3043503334541 |
7 | 330532432213 |
oct | 62575744075 |
9 | 18520105717 |
10 | 6811011133 |
11 | 2985702523 |
12 | 13a0bb1451 |
13 | 847105804 |
14 | 488802cb3 |
15 | 29ce3758d |
hex | 195f7c83d |
6811011133 has 2 divisors, whose sum is σ = 6811011134. Its totient is φ = 6811011132.
The previous prime is 6811011089. The next prime is 6811011139. The reversal of 6811011133 is 3311101186.
6811011133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3759774489 + 3051236644 = 61317^2 + 55238^2 .
It is a cyclic number.
It is not a de Polignac number, because 6811011133 - 29 = 6811010621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6811011098 and 6811011107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6811011139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3405505566 + 3405505567.
It is an arithmetic number, because the mean of its divisors is an integer number (3405505567).
Almost surely, 26811011133 is an apocalyptic number.
It is an amenable number.
6811011133 is a deficient number, since it is larger than the sum of its proper divisors (1).
6811011133 is an equidigital number, since it uses as much as digits as its factorization.
6811011133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The square root of 6811011133 is about 82528.8503070290. The cubic root of 6811011133 is about 1895.5585206097.
The spelling of 6811011133 in words is "six billion, eight hundred eleven million, eleven thousand, one hundred thirty-three".
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