Base | Representation |
---|---|
bin | 111111011100000011… |
… | …011111101110000101 |
3 | 20111211011001022200212 |
4 | 333130003133232011 |
5 | 2104000300211232 |
6 | 51143043045205 |
7 | 4630662650201 |
oct | 773403375605 |
9 | 214734038625 |
10 | 68116413317 |
11 | 26984a37567 |
12 | 11250070805 |
13 | 656713c814 |
14 | 34227c1b01 |
15 | 1b8a095eb2 |
hex | fdc0dfb85 |
68116413317 has 2 divisors, whose sum is σ = 68116413318. Its totient is φ = 68116413316.
The previous prime is 68116413271. The next prime is 68116413319. The reversal of 68116413317 is 71331461186.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52050597316 + 16065816001 = 228146^2 + 126751^2 .
It is a cyclic number.
It is not a de Polignac number, because 68116413317 - 228 = 67847977861 is a prime.
Together with 68116413319, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68116413319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34058206658 + 34058206659.
It is an arithmetic number, because the mean of its divisors is an integer number (34058206659).
Almost surely, 268116413317 is an apocalyptic number.
It is an amenable number.
68116413317 is a deficient number, since it is larger than the sum of its proper divisors (1).
68116413317 is an equidigital number, since it uses as much as digits as its factorization.
68116413317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72576, while the sum is 41.
The spelling of 68116413317 in words is "sixty-eight billion, one hundred sixteen million, four hundred thirteen thousand, three hundred seventeen".
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