Base | Representation |
---|---|
bin | 110001100110010101111… |
… | …1011100001001000001111 |
3 | 220010200111000011010202222 |
4 | 1203030223323201020033 |
5 | 1343141402112334411 |
6 | 22255341232005555 |
7 | 1302333620661113 |
oct | 143145373411017 |
9 | 26120430133688 |
10 | 6816850121231 |
11 | 21990121a6677 |
12 | 9211993908bb |
13 | 3a5a98243bb7 |
14 | 197d19d7b743 |
15 | bc4c66e84db |
hex | 6332bee120f |
6816850121231 has 2 divisors, whose sum is σ = 6816850121232. Its totient is φ = 6816850121230.
The previous prime is 6816850121201. The next prime is 6816850121233. The reversal of 6816850121231 is 1321210586186.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6816850121231 - 226 = 6816783012367 is a prime.
It is a super-2 number, since 2×68168501212312 (a number of 26 digits) contains 22 as substring.
Together with 6816850121233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6816850121233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3408425060615 + 3408425060616.
It is an arithmetic number, because the mean of its divisors is an integer number (3408425060616).
Almost surely, 26816850121231 is an apocalyptic number.
6816850121231 is a deficient number, since it is larger than the sum of its proper divisors (1).
6816850121231 is an equidigital number, since it uses as much as digits as its factorization.
6816850121231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 44.
The spelling of 6816850121231 in words is "six trillion, eight hundred sixteen billion, eight hundred fifty million, one hundred twenty-one thousand, two hundred thirty-one".
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