Base | Representation |
---|---|
bin | 11111000000100111100011… |
… | …01001100101111001010101 |
3 | 22221102222202220022011200201 |
4 | 33200103301221211321111 |
5 | 32414220033440102402 |
6 | 401010254154540501 |
7 | 20235430301622505 |
oct | 1740236151457125 |
9 | 287388686264621 |
10 | 68190955003477 |
11 | 1a8006924017a9 |
12 | 7793a44a37731 |
13 | 2c084c18b8667 |
14 | 12ba661acba05 |
15 | 7d3c0ad73687 |
hex | 3e04f1a65e55 |
68190955003477 has 2 divisors, whose sum is σ = 68190955003478. Its totient is φ = 68190955003476.
The previous prime is 68190955003351. The next prime is 68190955003487. The reversal of 68190955003477 is 77430055909186.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38807031561841 + 29383923441636 = 6229529^2 + 5420694^2 .
It is a cyclic number.
It is not a de Polignac number, because 68190955003477 - 231 = 68188807519829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68190955003487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34095477501738 + 34095477501739.
It is an arithmetic number, because the mean of its divisors is an integer number (34095477501739).
Almost surely, 268190955003477 is an apocalyptic number.
It is an amenable number.
68190955003477 is a deficient number, since it is larger than the sum of its proper divisors (1).
68190955003477 is an equidigital number, since it uses as much as digits as its factorization.
68190955003477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57153600, while the sum is 64.
The spelling of 68190955003477 in words is "sixty-eight trillion, one hundred ninety billion, nine hundred fifty-five million, three thousand, four hundred seventy-seven".
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