Base | Representation |
---|---|
bin | 10011111000010011110… |
… | …00010000000001110001 |
3 | 2102022010000022201210102 |
4 | 21330021320100001301 |
5 | 42142404234300341 |
6 | 1241443533042145 |
7 | 100231000204064 |
oct | 11741170200161 |
9 | 2368100281712 |
10 | 683065540721 |
11 | 243760765803 |
12 | b0471326355 |
13 | 4c549c13735 |
14 | 250bc2068db |
15 | 12b7c529c9b |
hex | 9f09e10071 |
683065540721 has 2 divisors, whose sum is σ = 683065540722. Its totient is φ = 683065540720.
The previous prime is 683065540693. The next prime is 683065540723. The reversal of 683065540721 is 127045560386.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 663514510096 + 19551030625 = 814564^2 + 139825^2 .
It is a cyclic number.
It is not a de Polignac number, because 683065540721 - 210 = 683065539697 is a prime.
Together with 683065540723, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (683065540723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341532770360 + 341532770361.
It is an arithmetic number, because the mean of its divisors is an integer number (341532770361).
Almost surely, 2683065540721 is an apocalyptic number.
It is an amenable number.
683065540721 is a deficient number, since it is larger than the sum of its proper divisors (1).
683065540721 is an equidigital number, since it uses as much as digits as its factorization.
683065540721 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 47.
The spelling of 683065540721 in words is "six hundred eighty-three billion, sixty-five million, five hundred forty thousand, seven hundred twenty-one".
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