68372013814081 has 2 divisors, whose sum is σ = 68372013814082. Its totient is φ = 68372013814080.

The previous prime is 68372013814067. The next prime is 68372013814133. The reversal of 68372013814081 is 18041831027386.

It is an a-pointer prime, because the next prime (68372013814133) can be obtained adding 68372013814081 to its sum of digits (52).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44651061801025 + 23720952013056 = 6682145^2 + 4870416^2 .

It is a cyclic number.

It is not a de Polignac number, because 68372013814081 - 2¹¹ = 68372013812033 is a prime.

It is a super-2 number, since 2×68372013814081² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (68372013814001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34186006907040 + 34186006907041.

It is an arithmetic number, because the mean of its divisors is an integer number (34186006907041).

Almost surely, 2^{68372013814081} is an apocalyptic number.

It is an amenable number.

68372013814081 is a deficient number, since it is larger than the sum of its proper divisors (1).

68372013814081 is an equidigital number, since it uses as much as digits as its factorization.

68372013814081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1548288, while the sum is 52.

The spelling of 68372013814081 in words is "sixty-eight trillion, three hundred seventy-two billion, thirteen million, eight hundred fourteen thousand, eighty-one".