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68372013814133 is a prime number
BaseRepresentation
bin11111000101111000110011…
…00110001001000101110101
322222002022010012101202002212
433202330121212021011311
532430201341014023013
6401225400341343205
720254500145255241
oct1742743146110565
9288068105352085
1068372013814133
111a870454386007
127802b55107b05
132c1c5b79bb893
1412c531a383421
157d87a64c86a8
hex3e2f19989175

68372013814133 has 2 divisors, whose sum is σ = 68372013814134. Its totient is φ = 68372013814132.

The previous prime is 68372013814081. The next prime is 68372013814151. The reversal of 68372013814133 is 33141831027386.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46401954362404 + 21970059451729 = 6811898^2 + 4687223^2 .

It is a cyclic number.

It is not a de Polignac number, because 68372013814133 - 28 = 68372013813877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (68372013814033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34186006907066 + 34186006907067.

It is an arithmetic number, because the mean of its divisors is an integer number (34186006907067).

Almost surely, 268372013814133 is an apocalyptic number.

It is an amenable number.

68372013814133 is a deficient number, since it is larger than the sum of its proper divisors (1).

68372013814133 is an equidigital number, since it uses as much as digits as its factorization.

68372013814133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1741824, while the sum is 50.

The spelling of 68372013814133 in words is "sixty-eight trillion, three hundred seventy-two billion, thirteen million, eight hundred fourteen thousand, one hundred thirty-three".