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68500417574773 is a prime number
BaseRepresentation
bin11111001001100111111110…
…00011100111011101110101
322222112120112212201121222101
433210303333003213131311
532434302323344343043
6401404353555502101
720266664130234442
oct1744637703473565
9288476485647871
1068500417574773
111a90a955a11958
127823a0b2b7931
132c2b73bc76282
1412cb61b8569c9
157dbcbe13224d
hex3e4cff0e7775

68500417574773 has 2 divisors, whose sum is σ = 68500417574774. Its totient is φ = 68500417574772.

The previous prime is 68500417574741. The next prime is 68500417574819. The reversal of 68500417574773 is 37747571400586.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53242151945284 + 15258265629489 = 7296722^2 + 3906183^2 .

It is a cyclic number.

It is not a de Polignac number, because 68500417574773 - 25 = 68500417574741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (68500417572773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34250208787386 + 34250208787387.

It is an arithmetic number, because the mean of its divisors is an integer number (34250208787387).

Almost surely, 268500417574773 is an apocalyptic number.

It is an amenable number.

68500417574773 is a deficient number, since it is larger than the sum of its proper divisors (1).

68500417574773 is an equidigital number, since it uses as much as digits as its factorization.

68500417574773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138297600, while the sum is 64.

The spelling of 68500417574773 in words is "sixty-eight trillion, five hundred billion, four hundred seventeen million, five hundred seventy-four thousand, seven hundred seventy-three".