Base | Representation |
---|---|
bin | 11111001001110110111010… |
… | …11100001000110111010111 |
3 | 22222120100021012221111110001 |
4 | 33210323131130020313113 |
5 | 32434420243014343104 |
6 | 401412202223312131 |
7 | 20300400044463241 |
oct | 1744733534106727 |
9 | 288510235844401 |
10 | 68508443512279 |
11 | 1a9132a4395561 |
12 | 782548b14b647 |
13 | 2c2c41a99b214 |
14 | 12cbb7d753091 |
15 | 7dc0dda52aa4 |
hex | 3e4edd708dd7 |
68508443512279 has 2 divisors, whose sum is σ = 68508443512280. Its totient is φ = 68508443512278.
The previous prime is 68508443512261. The next prime is 68508443512321. The reversal of 68508443512279 is 97221534480586.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 68508443512279 - 235 = 68474083773911 is a prime.
It is a super-3 number, since 3×685084435122793 (a number of 42 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 68508443512279.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68508443512879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34254221756139 + 34254221756140.
It is an arithmetic number, because the mean of its divisors is an integer number (34254221756140).
It is a 1-persistent number, because it is pandigital, but 2⋅68508443512279 = 137016887024558 is not.
Almost surely, 268508443512279 is an apocalyptic number.
68508443512279 is a deficient number, since it is larger than the sum of its proper divisors (1).
68508443512279 is an equidigital number, since it uses as much as digits as its factorization.
68508443512279 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116121600, while the sum is 64.
The spelling of 68508443512279 in words is "sixty-eight trillion, five hundred eight billion, four hundred forty-three million, five hundred twelve thousand, two hundred seventy-nine".
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