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70099439 is a prime number
BaseRepresentation
bin1000010110110…
…10000111101111
311212220102100112
410023122013233
5120421140224
610542250235
71510556354
oct413320757
9155812315
1070099439
1136629823
121b58697b
13116a4b77
14944a62b
15624a30e
hex42da1ef

70099439 has 2 divisors, whose sum is σ = 70099440. Its totient is φ = 70099438.

The previous prime is 70099399. The next prime is 70099441. The reversal of 70099439 is 93499007.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 70099439 - 212 = 70095343 is a prime.

It is a super-3 number, since 3×700994393 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 70099441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 70099396 and 70099405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (70099499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35049719 + 35049720.

It is an arithmetic number, because the mean of its divisors is an integer number (35049720).

Almost surely, 270099439 is an apocalyptic number.

70099439 is a deficient number, since it is larger than the sum of its proper divisors (1).

70099439 is an equidigital number, since it uses as much as digits as its factorization.

70099439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61236, while the sum is 41.

The square root of 70099439 is about 8372.5407732659. The cubic root of 70099439 is about 412.3235883551.

The spelling of 70099439 in words is "seventy million, ninety-nine thousand, four hundred thirty-nine".