Base | Representation |
---|---|
bin | 110011110000010000001… |
… | …0110001101001101111111 |
3 | 221011222220210110100002022 |
4 | 1213200200112031031333 |
5 | 1413014420141100044 |
6 | 23043400534350355 |
7 | 1332616660650035 |
oct | 147404026151577 |
9 | 27158823410068 |
10 | 7113008534399 |
11 | 22a2678977919 |
12 | 96a6701bb3bb |
13 | 3c79a52074b1 |
14 | 1a83b2c04555 |
15 | c505b9c43ee |
hex | 6782058d37f |
7113008534399 has 2 divisors, whose sum is σ = 7113008534400. Its totient is φ = 7113008534398.
The previous prime is 7113008534377. The next prime is 7113008534419. The reversal of 7113008534399 is 9934358003117.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7113008534399 - 228 = 7112740098943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 7113008534399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7113008534899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3556504267199 + 3556504267200.
It is an arithmetic number, because the mean of its divisors is an integer number (3556504267200).
Almost surely, 27113008534399 is an apocalyptic number.
7113008534399 is a deficient number, since it is larger than the sum of its proper divisors (1).
7113008534399 is an equidigital number, since it uses as much as digits as its factorization.
7113008534399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 7113008534399 in words is "seven trillion, one hundred thirteen billion, eight million, five hundred thirty-four thousand, three hundred ninety-nine".
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