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7113425233181 is a prime number
BaseRepresentation
bin110011110000011100100…
…1011110010010100011101
3221012000222211112211100112
41213200321023302110131
51413021243324430211
623043510141535405
71332633210561221
oct147407113622435
927160884484315
107113425233181
1122a2872108883
1296a767874565
133c7a40644717
141a84122b4781
15c508338588b
hex678392f251d

7113425233181 has 2 divisors, whose sum is σ = 7113425233182. Its totient is φ = 7113425233180.

The previous prime is 7113425233151. The next prime is 7113425233219. The reversal of 7113425233181 is 1813325243117.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7025017725625 + 88407507556 = 2650475^2 + 297334^2 .

It is an emirp because it is prime and its reverse (1813325243117) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-7113425233181 is a prime.

It is a super-2 number, since 2×71134252331812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7113425233151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3556712616590 + 3556712616591.

It is an arithmetic number, because the mean of its divisors is an integer number (3556712616591).

Almost surely, 27113425233181 is an apocalyptic number.

It is an amenable number.

7113425233181 is a deficient number, since it is larger than the sum of its proper divisors (1).

7113425233181 is an equidigital number, since it uses as much as digits as its factorization.

7113425233181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 41.

The spelling of 7113425233181 in words is "seven trillion, one hundred thirteen billion, four hundred twenty-five million, two hundred thirty-three thousand, one hundred eighty-one".