Base | Representation |
---|---|
bin | 1101010001001000… |
… | …01011010100011101 |
3 | 200101102020001210121 |
4 | 12220210023110131 |
5 | 104041443220013 |
6 | 3134451034541 |
7 | 341341461202 |
oct | 65044132435 |
9 | 20342201717 |
10 | 7123023133 |
11 | 3025840786 |
12 | 146959ba51 |
13 | 89694abb5 |
14 | 4b8021ca9 |
15 | 2ba51a58d |
hex | 1a890b51d |
7123023133 has 2 divisors, whose sum is σ = 7123023134. Its totient is φ = 7123023132.
The previous prime is 7123023097. The next prime is 7123023161. The reversal of 7123023133 is 3313203217.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7123022404 + 729 = 84398^2 + 27^2 .
It is an emirp because it is prime and its reverse (3313203217) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 7123023133 - 217 = 7122892061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 7123023098 and 7123023107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7123023533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3561511566 + 3561511567.
It is an arithmetic number, because the mean of its divisors is an integer number (3561511567).
Almost surely, 27123023133 is an apocalyptic number.
It is an amenable number.
7123023133 is a deficient number, since it is larger than the sum of its proper divisors (1).
7123023133 is an equidigital number, since it uses as much as digits as its factorization.
7123023133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 25.
The square root of 7123023133 is about 84398.0043188226. The cubic root of 7123023133 is about 1924.0725848520.
The spelling of 7123023133 in words is "seven billion, one hundred twenty-three million, twenty-three thousand, one hundred thirty-three".
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